inequalities in a case statement in ksh

From: Spalding, Steve <SSPALDIN_at_mem-ins.com>
Date: Tue, 31 Mar 1998 14:39:49 -0600

Hello all!

Since my question earlier today went so well, I thought that I would try
another. I'm writing a script file using a case statement, and I want to
use inequalities with it but don't know how. Here is what I have right
now:
   case "$capacity" in
           [93 - 96] if [ $severity -lt 1 ];then
                                severity=1
                                fi #if [ $severity -lt 1 ];then
                                ;;
            [97 - 99] if [ $severity -lt 2 ];then
                                severity=2
                                page=true
                                fi #if [ $severity -lt 2 ];then
                                ;;
              100) if [ $severity -lt 3 ];then
                                severity=3
                                page=true
                                fi #if [ $severity -lt 3 ];then
                                ;;
    esac #case "$capacity" in

Let's say that in the last case I wanted to catch any value above 100
instead of just 100; how would I set that up? Here is what I have tried
using:

> 100 if [ $severity -lt 3 ];then

        [ > 100 ] if [ $severity -lt 3 ];then

       [ -gt 100] if [ $severity -lt 3 ];then

but nothing seems to want to work. Any ideas?

Thanks!

PS - Lawrence Decker - I tried responding to your email earlier, but I
keep getting this text in a returned mail message:

Your Message
    To: 'ldecker_at_pbchcd.state.fl.us'
    Subject: FW: Pop up message
Was not delivered for the following reasons:
    Delivery failed to SMTP:ldecker_at_pbchcd.state.fl.us.
    Reason: 0 (transfer failed)
    diagnostic: 0 (OR name (Email address) unrecognized).
    MSEXCH:IMS:MEM:EXCH1:MEM_CO_NT1 3902 (000B0981) Host Unknown.


Stephen Spalding
Associate System Administrator
sspaldin_at_mem-ins.com
Missouri Employers Mutual Insurance
Received on Tue Mar 31 1998 - 22:43:46 NZST

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