Thanks to everyone who replied.
SOLUTION:
(remember D0 = D000)
(oh also where you have LUN that is actual unit number) so:
unit number = D0 = D000 = Dx0y
rz = rz(y as letter)( ( 8 * bus number) + x )
where (y as letter) means if it is 0 then letter is a,
1=b,2=c,3=d,4=e,5=f,6=g,7=h
So D0 = rza( (8*busnumber) + 0 )
In this case I'm guessing that your HSZ is sitting on SCSI bus 5.
So to continue D1 = D001 so
rzb( ( 8* 5) + 0 ) = rzb40
D102 is
rzc( ( 8 * 5 ) + 1 ) = rzc41
Here is the solution worded differently:
It's based on bus number first, then the D# is the target number, then
you
apply the lun. Formula is (Bus * 8) + SCSI target ID. Throw your LUN
in
and you have it. So for your example, rz40 is on bus 5 so;
D0
( 5*8 ) + 0 = rz40
40 + 0 = 40 =rz40
D102
( 5 * 8 ) +1 = 41 = rz41 add a LUN of 2 ({ 0...7} = { a...h }) and you
have
rzc41
-Ric
-----
R. Richard Hirtler Senior Consultant/Northeast Region
hirtler_at_colltech.com Collective Technologies
-----
It is the province of knowledge to speak, and it is the privilege of wisdom
to listen. ‹Oliver Wendell Holmes, Sr.
ORIGINAL QUESTION:
>
> How does Tru64 map logical units on an array controller to a UNIX device?
>
> I have a HSZ70 and a 8200 running 4.0F. The HSZ70 has the following units
> defined:
>
> LUN Uses
> D0 M0
> D1 S1
> D100 S100
> D101 M101
> D102 M102
>
> These LUN devices map to rz devices in /dev. I understand that MAKEDEV is
> used to create the rz devices. However, I am unclear on how the mapping is
> defined.
>
> For example, D0 maps to rz40. D1 maps to rzb40. The syntax for MAKEDEV might
> be:
>
> # /dev/MAKEDEV rz40 rzb40
>
> But how does the system ³know² which LUN to map to which device?
>
> TIA,
>
> -Ric
> -----
> R. Richard Hirtler Senior Consultant/Northeast Region
> hirtler_at_colltech.com Collective Technologies
> -----
> It is the province of knowledge to speak, and it is the privilege of wisdom to
> listen. ‹Oliver Wendell Holmes, Sr.
>
>
>
>
>
Received on Fri Oct 27 2000 - 14:32:49 NZDT