Trying to figure out how disklabel configure the
default partitions scheme for a drive when the disktype
is not specified or no entry in /etc/disktab.
According to /etc/disktab, the following are general
rules for partitioning scheme:
# All partition sizes contain space for bad sector tables unless
# the device drivers fail to support this. Smaller disks may
# not have all partitions and all disks have no defaults for
# the `h' partition. The strategy here is that `a' always
# has the same amount for all disks (for the most part). The `b' partition is
# twice `a' while `c' is always the entire disk. The
# sum of `d', `e', and `f' is equal to `(c - (a + b))' which is everything else.
#
# For all but the really small disks (like the RZ23) the partition sizes are:
#
# a is 64MB in size
# b is 128MB in size
# c is the whole disk
# d,e,f is 1/3 of partitions g and h ((c - (a + b))/3)
# g is 400MB (or rest of disk)
# h is rest of disk (or zero)
#
However, when I ran disklabel -nrw /dev/rrz... for a particular drive,
aside from the a,b,and c
partitions, I only get the g and h partitions defined. Both were
around ~900MB which is not as stated above. For another smaller drive,
I do get the d,e, and f partition defined. Any idea on why this is so?
Thanks in advance.
--
<------------------------------>
Tri Tran
UC Irvine-Office of Academic Computing
Phone: (949)824-5887 email: thtran_at_uci.edu
Received on Tue Apr 11 2000 - 00:44:43 NZST